Y=16x^2+30x+4

Solution for Y=16x^2+30x+4 equation:

=16Y^2+30Y+4

We move all terms to the left:

-(16Y^2+30Y+4)=0

We get rid of parentheses

-16Y^2-30Y-4=0

a = -16; b = -30; c = -4;
Δ = b2-4ac
Δ = -302-4·(-16)·(-4)
Δ = 644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{644}=\sqrt{4*161}=\sqrt{4}*\sqrt{161}=2\sqrt{161}$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{161}}{2*-16}=\frac{30-2\sqrt{161}}{-32}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{161}}{2*-16}=\frac{30+2\sqrt{161}}{-32}
$